Question

Two people are pushing a stalled car. The mass of the car

is 1850 kg. One person applies a force of 275 N to the car, while

the other applies a force of 395 N. Both forces act in the same

direction. A third force of 560 N also acts on the car, but in a

direction opposite to that in which the people are pushing. This

force arises because of friction and the extent to which the pavement opposes the

motion of the tires. Find the acceleration of the car.​

Answer 1

Answer: 0.059m/s^2.

..

Answer 2

The acceleration of the car is 0.059 m/s².

Given: The mass of the car is 1850 kg.

The magnitude of forces applied in the same direction= 275 N and 395 N

The magnitude of force applied in opposite direction = 560 N

To Find: The acceleration of the car.​

Solution:

• We need to find the acceleration of the car, so we can use the formula

                    ∑ F = m × a       [ m = mass, a = acceleration ]

• We can see that two forces are acting in the same direction and the third force is friction, which always acts in opposite direction.

According to the given conditions and values, we frame an equation,

   ∴    395 + 275 - 560 = 1850 × a           [ a = acceleration ]

   ⇒   a = 110 / 1850

            = 0.059 m/s²

Hence,  the acceleration of the car is 0.059 m/s².

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