Question

Two people start running around a track at the same time. Both will run 12 laps. If runner a runs each lap in 8 minutes and runner b runs each lap in 11 minutes, how much sooner will runner a finish running 12 laps than runner b?

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Runner a will finish 36 minutes sooner than runner b

Step-by-step explanation:

a runs each lap in 8 minutes

a runs 12 laps in minutes = $12 \times 8 = 96$

Runner b runs each lap in 11 minutes

b runs 12 laps in minutes = $12 \times 11 = 132$

Difference between time in completing 12 laps = 132 - 96 = 36 minutes

Hence runner a will finish 36 minutes sooner than runner b