Two periodic waves of amplitudes A1 and A2 pass thorough a region. If A1 > A2, the difference in the maximum and minimum resultant amplitude possible is
(a) 2A1
(b) 2A2
(c) A1 + A2
(d) A1 − A2.
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Answer:
B
Explanation:
The maximum amplitude will be obtained when both waves will be in phase, which is (A1 +A2). Similarly minimum amplitude will be the result of opposite phase, which is (A1- A2). Thus the difference will be (A1 +A2) - ( A1 - A2) which is 2A2
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