Question

two perpendicular vectors having magnitudes of4 units and 3 units are added. Their resultant has the magnitude of:​

Answer 1

Given:-

two perpendicular vectors having magnitudes of4 units and 3 units are added.

To Find:-

• Their resultant.

Solution:-

Let

$|A| = 4$

$|B| = 3$

$\theta = 90\degree$

The Resultant Vector is

$|A + B| = \sqrt{ { |A| }^{2} + { |B| }^{2} + 2 |A| |B| \cos(90) }$

$= > \sqrt{ {4}^{2} + {3}^{2} + 2(4)(3) \times 0}$

As, cos90°=0

$= > \sqrt{16 + 9}$

$= > \sqrt{25}$

$= > 5 \: units$

∴ The resultant has the magnitude of 5 units.

Answer 2

Hey mate

Hope it will help you