Question

Two persons A & B started their
journey from points P & Q respectively,
towards each other at 8 am, IF A increases
his speed by 12.5% then he will be 10 min
before. If B increases his speed by 25%
then at what time B completed his
journey. If speed of B is 20% more than A.
दो व्यक्ति A और B क्रमशः P और Q से पूर्वाहन ४ बजे
एक-दूसरे की ओर चलकर अपनी यात्रा प्रारंभ करते है। यदि
A ने अपनी गति 12.5% बढ़ा दी तो वह 10 मिनट पहले
पहुँच जाता है। यदि B अपनी गति 25% बढ़ाता है तो किस
समय B ने अपनी यात्रा पूरी की? यदि B की गति A से
20% अधिक है।
a)9:00 am b) 8:45 am
0)9:15am d) 8:40 am
38.​

Answer 1

Answer:

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Answer 2

Answer:

PERSON A -

Speed - 8:9

TIME - 9:8

TIME DIFFERENCE WILL BE 1 unit which is given as 10 min = 1unit=10min

usual time taken by A - 90 MIN

NOW ASSUME 8 BE the usual speed of A .

then DISTANCE = 8×90 = 720

B is 20% more faster than A then speed of B =8×1.2 = 9.6

now given than B Increases his speed by 25% i.e = 4:5

4 unit = 9.6 then 5 unit = 12

time taken by B = 720/12 = 60MIN

8:00+ 1:00 = 9:00 AM