Question

Two persons A and B, A wins by a margin of 192 votes.if A gets 58% of the total votes, find thetital votes polled

Answer 1

Answer: ∴ The total votes polled are 1200, where A has polled 696 votes and B has polled 504 votes.

Step-by-step explanation:

Let the votes polled by A and B be x and y respectively. Let the total votes be z.

∴ $x + y = z$

∴ $x - y = 192$

A has polled about 58% of entire votes.

∴ $x = \frac{58z}{100}$

$y = \frac{100z - 58z}{100} = \frac{42z}{100}$

Difference in votes:

$x - y = \frac{58z}{100} - \frac{42z}{100} = 192$

∴ $x - y = \frac{16z}{100} = 192$

∴ $16z = 192*100$

∴ $z = 1200$

Now, we get 2 simultaneous equations.

$x + y = 1200 (i)\\x - y = 192(ii)$

Upon adding equation 1 and 2...

$2x = 1392\\x = 696$

Upon subtracting equation 2 from 1

$2y = 1008\\y = 504$

Answer: ∴ The total votes polled are 1200, where A has polled 696 votes and B has polled 504 votes.