two persons A and B have 30 sheep between them. They sell them at different prices but each receives the same amount. If A had sold his at B's price, he would have received Rs. 3200 and if B had sold his at A's price, he would have received Rs.2450. How many sheep belonged to A ?
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Answer:
Step-by-step explanation:
Let the number of sheep of A be X.
Let the number of sheep of B be Y.
Therefore,
X+Y =30................................ (1)
Let the selling price of A's sheep be P.
Let the selling price of B's sheep be Q.
Now as per question,
P×X =Q× Y. ......,..................... (2)
Also,
X×Q= 3200.
Or, Q=(3200/X)
Again,
Y×P =2450.
P=(2450/Y)
Now putting the value of P and Q in equation (2) we get.
(2450/Y)X = (3200/X) Y
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