Question

Two persons A and B start from the same location and walked around a square in opposite directions with constant speeds. The square has side 60m. Speeds of A and B are 4m/s and 2m/s respectively. When will they meet first time?

Answer 1

PLEASE ASK THEM...........

Answer 2

Answer:

They will meet after 40 sec.

Explanation:

Given that,

Side of square = 60 m

Speed of A = 4 m/s

Speed of B = 2 m/s

Two persons A and B start from the same location and walked around a square in opposite directions with constant speeds.

The distance is the product of the speed and time.

Person A covers a distance = 4 t

Person B covers a distance =2 t

The total distance= perimeter of square

$4t+2t=4\times60$

$6t=240$

$t=40$

Hence, They will meet after 40 sec.