Question

Two persons a and b start moving simultaneously towards each other from two places pand q respectively.They meet 40km from q.If the ratio of their speeds is 1:4,find the distance between p and q?

Answer 1

Answer:

pq = 50 km

Step-by-step explanation:

Given that;

a and b start moving simultaneously towards each other from p and q respectively.

See the figure at the attachment for diagrammatic representation.

Let the point a and b meet = z

So, pq = pz + zq

Given; zq = 40km

Distance = Speed x Time

Time = Distance / Speed

Let, the speed of ‘a’ = x km

So, the speed of ‘b’ = 4x km

(The ratio of speed between a and b is 1:4)

Let the distance travelled by ‘a’ = y km

The distance travelled by ‘b’ = 40 km (Given)

So, zq = 40

For ‘a’:

Time (T) = y / x  ……. Eq (1)

For ‘b’:

Time (T) = 40 / 4x  ……..Eq (2)

From Eq (1) & Eq (2),

y / x = 40 / 4x

=> 4y = 40

=> y = 10

pz = y

Therefore, pz = 10

Now,

pq = pz + zq

    = 10 + 40

    = 50 km

Therefore, the distance between p and q (pq) = 50km

Answer 2

Answer:

50

Step-by-step explanation:

Speed of A is 'v'  

Speed of B is '4v'

Travelled by B is 40 km  

Time to meet =  

40 / 4v = 10 /v

Distance covered by A is = v ( 10/v) = 10 km

So total distance is 10 + 40 = 50km

Hence the distance between p and q is 50.