Question

two persons A and B together can do a work in 10 days the same work can be finished in 18 days if a working for 12 days and B walk around for 6 days find the time required for each one of them to finish the work if they work alone

Answer 1

M1D1 = m2d2

(A+B)×10= 12A+6B

10A + 10B = 12A+6B

2A = 4B

A = 2B

A/B =2/1

IT MEANS A CAN DO 2 UNIT OF WRK IN ONE DAY & B CAN DO 1 UNIT OF WRK IN 1 DAY.

TOGETHER THEY WRKD FOR 10 DAYS.

IT MEANS TOTAL WRK DONE BY THEM =( 2+1)×10

= 30UNIT.

SO A CAN DO THE SAME WRK ALONE = 30/2 = 15DAYS

B CAN DO THE SAME WRK = 30/1 = 30 DAYS