Question

Two persons Abhi and Sunny can do a job in 36 days together. Sunny can do the same job in 42
days alone. They started working together and after working for 6 days, Sunny is replaced by a
third person Rocky, whose efficiency is double of that of Sunny. Find in how many days the
remaining work will be completed by both Abhi and Rocky together?​

Answer 1

Answer:

Step-by-step explanation:

Work done by Shyam and Rahim in 8 days = 8/32 = 1/4

Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4

Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days.

One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96

Hence, the total work can be done by Shyam and Ram together in 96/5 days.

 

Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.