Two persons are holding a rope of negligible weight tightly at its end so that it is horizontal . A 15 kg weight is attached to the rope at the mid point which now no longer remains horizontal. The minimum tension required to completely straighten the rope is
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The tension required to bring the string into horizontal position can be found out using the following formulae.
2Tsinx = mg
The following equation is true for body which attains equilibrium. Also, when the body will be in equilibrium the angle formed will be 0.
Therefore,
T = mg/2sin x , where x= 0
T = mg/ 2 sin 0, where the value of sin0 = 0
Then, the amount of tension required is infinite.
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