Two persons are walking beside a railway track at respective speeds of 2 and 4 km per hour in the same direction. A train came from behind them and crossed them in 90 and 100 seconds, respectively. The time, in seconds, taken by the train to cross an electric post is nearest to
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Two person to be A and B
A = 2km/hr and B = 4 km/hr
Speed of the train = t km/hr
Given, Train crosses A in 90 seconds (Length of the train is the distance)
t – 2 in 90 seconds and t – 4 in 100 seconds
Ratio of speed is opposite to time
(t – 2) 90 = (t - 4) 100
Solving t = 22km/hr
For A, Speed = t – 2 = 20 km/hr in 90 seconds
So travelling at 22 km/hr ----> (90×20)/22 ≅ 82
Answer = 82 seconds
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Answer:
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