Question

two persons just manage to push a block from left to right direction along a horizontal level road with uniform velocity when the same block is pushed by three persons in same direction a constant acceleration of 0.2 msis produced in the block is the 5 persons push block in same direction together then magnitude of acceleration of the block will be

Answer 1

When 2 person pulls the box it will move to the right with constant speed

So applied force = friction force

F_f = 2FFf​=2F

When 3 person apply force on it

3F - F_f = ma3F−Ff​=ma

3F - 2F = 0.2m3F−2F=0.2m

Now when 5 person apply the same force then we have

5F - F_f = ma5F−Ff​=ma

5F - 2F = ma5F−2F=ma

3F = ma3F=ma

from above equation F = 0.2m

3*0.2m = ma3∗0.2m=ma

a = 0.6 m/s^2a=0.6m/s2

so acceleration will be 0.6 m/s^2