Question

Two Persons of Mass 50 kg & 60 kg stand at a Distance of 1 m from each Other. What will be the Force of Gravitation between them?

(Hint :- $\bold {F = G \times \frac{M \times m}{d^2} }$)

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Answer 1

Answer:-

Given:

Mass of first person (M) = 50 kg

Mass of second person (m) = 60 kg

Distance between them (d) = 1 m

We know that,

Gravitational force (F) = GMm/d²

[ where G is the gravitational constant ]

• G = 6.67 × 10⁻¹¹ Nm²/kg²

So,

⟶ F = (6.67) × (10)⁻¹¹ × (50) × (60) / (1)²

⟶ F = 6.67 × 5 × 6 × 10² × 10⁻¹¹

⟶ F = 200.1 × 10⁻¹¹⁺²

[ aᵐ × aⁿ = aᵐ⁺ⁿ ]

⟶ F = 2001 × 10⁻¹ × 10⁻¹¹⁺²

⟶ F = 2.001 × 10³⁻¹⁻⁹

⟶ F = 2.001 × 10⁻⁷ N

∴ The gravitational force between them is 2.001 × 10⁻⁷ N.

Answer 2

Given :-

Mass of the First Person, M = 60 Kg

Mass of the Second Person, m = 50 Kg

Distance between the Two Persons, d = 1 m

To Find :-

The Force of Gravitation between them...

Solution :-

By Using the Formula, $\bold {F = G \times \frac{M \times m}{d^2} }$, we get -

F = $\bold {\frac{6.673 \times 10^{-11} \times 50 \times 60}{1^2}}$

$\Rightarrow 6.673 \times 5 \times 6 \times 10^2 \times 10^{-11}\\\\\Rightarrow 200.19 \times 10^{(-11) + 2}\\\\\Rightarrow 2.0019 \times 10^2 \times 10^{(-9)}\\\\= \bold {2.0019 \times 10^{(-7)} N}$

∴ The Force of Gravitation between them is $\bold {2.0019 \times 10^{(-7)}\: Newton}$...