Two persons on the same side of a tall building notice the angle of elevation of the top of the building to be 30° and 60° respectively. If the height of the building is 72 m, Find the distance between two persons. (√3=1.73)
khushichiya:
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in triangle dbc
tan 60 =cd/bd
√3=72/bd
bd=72*√3/3
bd=24*1.73
bd=41.52
in triangle abc
tan 30 =cb/ab
1/√3=72/ab
ab=72*√3
ab=124.56
distance between person
ad=ab-bd
=124.56-41.52
=83.04 m
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