Two persons Shyam and Rahim can do a job in 32 days together. Rahim can do the same job in 48 days alone. They started working together and after working 8 days Rahim is replaced by a third person Ram whose efficiency is half that of Rahim. Find in how many days the remaining work will be completed by both Shyam and Ram together?
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one day work of,
shyam
=1/32-1/48
=3-2/96
=1/96part
work done by shyam and rahim in 8 days
=8×(1/96+1/48)
=8×(1+2/96)
=8×(3/96)
=8×1/32
=1/4
rest work =1-1 /4
=3/4
Ram effienciency =half of rahim
so one day work of,
ram =1/48×2=1/96
ram and shyam = 1/96+1/96=2/96=1/48
since ram and shyam complete
1 work =48days
so 1/4 work=48×1/4
=12days
shyam
=1/32-1/48
=3-2/96
=1/96part
work done by shyam and rahim in 8 days
=8×(1/96+1/48)
=8×(1+2/96)
=8×(3/96)
=8×1/32
=1/4
rest work =1-1 /4
=3/4
Ram effienciency =half of rahim
so one day work of,
ram =1/48×2=1/96
ram and shyam = 1/96+1/96=2/96=1/48
since ram and shyam complete
1 work =48days
so 1/4 work=48×1/4
=12days
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