Math, asked by akhilrao361, 11 days ago

Two persons were approaching each other at 12 km/hr and 24km/hr respectively. A train moving in the same direction as the faster man took 25 seconds to cross him and 15 seconds to cross the other one. Find the speed of the train(in km/hr).​

Answers

Answered by amitnrw
0

Given: Two persons were approaching each other at 12 km/hr and 24km/hr respectively.

A train moving in the same direction as the faster man took 25 seconds to cross him and 15 seconds to cross the other one.

To Find :  the speed of the train(in km/hr).​

Solution:

Train Speed = T km/hr

A train moving in the same direction as the faster man took 25 seconds to cross him

Relative speed = (T - 24 ) km/hr

Time taken  = 25 sec = 25/3600  hrs

Length of train = (T - 24) 25/3600  km

Train moving in the opposite direction as the slower man took  15 seconds to cross

Relative speed = (T + 12 ) km/hr

Time taken  = 15 sec = 15/3600  hrs

Length of train = (T + 12) 15/3600  km

Equate Length of train

(T - 24) 25/3600  =  (T + 12) 15/3600

=> 25T -  600 = 15T + 180

=> 10T = 780

=> T = 78

Speed of Train = 78 km/hr

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Answered by vaibhav13550
0

Step-by-step explanation:

Train Speed = T km/hr

A train moving in the same direction as the faster man took 25 seconds to cross him.

Relative speed = (T-24 ) km/hr

Time taken = 25 sec = 25/3600 hrs.

Length of train = (T-24) 25/3600 km

Train moving in the opposite direction as the slower man took 15 seconds to cross

Relative speed=(T+12)km/hr

Time taken = 15 sec = 15/3600 hrs

Length of train = (T + 12) 15/3600 km

Equate Length of train

(T-24) 25/3600 = (T+12) 15/3600

=> 25T 600 = 15T + 180

=> 10T= 780

=> T = 78

Speed of Train = 78 km/hr.

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