two pieces A and B can fill a tank in 24 minutes and 32 minutes respectively while pipe C can empty it in 16 minutes if all three pipes are opened find the time taken to fill the tank
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Step-by-step explanation:
Work done by pipe A in 1 minute=1/24th
Work done by pipe B in 1 minute=1/32th
Work done by pipe C in 1 minute=-(1/16th) ( because it empties)
Work done by (A+B+C) in 1 minute =1/24+1/32-1/16
=4/96+3/96-6/96
=1/96
So, (A+B+C) can fill an empty cistern in 96 minutes= 1 hour and 36 minutes.
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Answer:
72
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