Question

Two Pieces of length 23_5 m and 33m are cut off from a rope I'm long what is the length of the reamaing rope .​

Answer 1

Step-by-step explanation:

Answer⟹288,298and304

\tt\large\underline\purple{Let:-}

Let:−

\sf{:\longmapsto First\: multiple\:of\:8=x}:⟼Firstmultipleof8=x

\sf{:\longmapsto Second\: multiple\:of\:8=x+8}:⟼Secondmultipleof8=x+8

\sf{:\longmapsto Third\: multiple\:of\:8=x+16}:⟼Thirdmultipleof8=x+16

\tt\large\underline\purple{To\: Find:-}

ToFind:−

\tt{:\longmapsto The\:three\:multiple\:of\:8=?}:⟼Thethreemultipleof8=?

\tt\large\underline\purple{Explaination:-}

Explaination:−

\tt{:\longmapsto Sum\:_{(multiples)}=888}:⟼Sum

(multiples)

=888

\tt{:\longmapsto x + (x + 8) + (x + 16) = 888}:⟼x+(x+8)+(x+16)=888

\tt{:\longmapsto x + x + 8 + x + 16 = 888}:⟼x+x+8+x+16=888

\tt{:\longmapsto 3x + 24 = 888}:⟼3x+24=888

\tt{:\longmapsto 3x = 888 - 24}:⟼3x=888−24

\tt{:\longmapsto 3x = 864}:⟼3x=864

\tt{:\longmapsto x = 288}:⟼x=288

Now calculate multiples here :-]

\sf{:\longmapsto First\: multiple \:(x) = 288}:⟼Firstmultiple(x)=288

\sf{:\longmapsto Second\: multiple\:(x + 8) = 288 + 8=296}:⟼Secondmultiple(x+8)=288+8=296

\sf{:\longmapsto Third\: multiple\:(x + 16)=288 + 16 = 304}:⟼Thirdmultiple(x+16)=288+16=304

\sf\small\underline{Hence, \:\:required\: multiples=288,\:\:,296\:\:,304}

Hence,requiredmultiples=288,,296,304