two pieces of length 5 6/7 m and 2 3/5 m are cut off from a rope 20m long. What is the length of the remaining rope ?
Answers
Answer:
Given
Total length of the rope= 20m
Length of the first piece = 5 6/7 = 46/7m
Length of the second pieces = 2 3/5 = 23/5 m
Let the length of third piece be = x
x= total length-( length of the first piece + length of the second piece )
= 20-(46/7+ 23/5
= 20-( 46+46)/7
= 20/1- 92/7
=(220-92)/7
=128/7m
Therefore
Length of the remaining piece=x= 128/7m
Step-by-step explanation:
I hope this helps you
Step-by-step explanation:
Total length of the rope 20m
Length of the first iece = 5 6/7 = 46/7 * m
Length of the second ces = 2 3/5 = 23/5 * m
Let the length of third piece be = x
x = total length-( length of the first piece + length of the second piece)
=20-(46/7+23/5
=20-(46+46)/7
=20/1-92/7
=(220-92)/7
=128/7m
Therefore
Length of the remaining ece = x = 128/7 * m.