two pieces of length s 23/5m and 33/10m are cut off from a rope 11m long what is the length of the remaining rope
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Length of rope = 11m
Length of first piece = 2 3/5 m = 13/5 m
Length of second piece = 3 3/10m = 33/10 m
length of remaining piece =
11 - 13/5 - 33/10
= (110 - 26 - 33)/10
= (110 - 59)/10
= 51/10
= 5.1 m
Answer - Length of remaining piece is 5.1m
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