two pieces of lengths 2 1/7 meters and 5 3/14 meters are cut off from a rope 12meters long.what is the length of the remaining rope
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Answer:
first piece =2(1/7)=15/7
second piece=5(3/14)=73/14
by which we know that we have to add 15/7+73/14
take LCM of 7 and 14 =14
15(2)/7(2)+73(1)/14(1)=30+73/14=103/14
now subtract 12/1-103/14
take LCM of 1,14=14
12(14)/1(14)-103(1)/14(1)
=168-103/14=65/14m
hence the length of the remaining rope is 65/14=4(9/14)
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