Math, asked by nallaguntarajitha, 6 months ago

two pieces of lengths 2(3/5)m and 3(3/10)m are cut off from a rope 11m long. what is the length of the remaining rope? ​

Answers

Answered by mmanjeetkaurin
8

Answer:

Given

Total length of the rope =11 m

If the rope is cut into 3 pieces

Length of the first piece = 2 3/5=13/5 m

Length of the second piece =3 3/10=33/10 m

We have to find out length of the third piece =x

x= total length -(length of the first piece + length of the second piece)

=11 - (13/5+33/10)

=11-[(26+33)/10]

=11/1 - 59/10

=(110-59)/10

=51\10

=5 1/10 m

Therefore

Length of the remaining piece =x =5 1/10 m

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