Two pieces of lengths 2 3/5m and 3 3/10m are cut off from a rope 11m long.What is the length of the remaining rope?
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13
Answer:
1.8 m
Step-by-step explanation:
the lengths are 2 3/5 and 3 3/10
first change mixed fraction into improper fraction
2 3/5 = 2*5+3/5 = 13/5
3 3/10= 3*10+3/5 = 33/5
add them
13/5 + 33/5 = 46/5
subtract this from 11
11 - 46/5 = 1.8
therefore the answer is 1.8 m
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