Question

Two pieces of lengths 9/11m and 13/22m are cut from a 2m long rope. What is the length of the remaining rope
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Answer 1

Answer:

Step-by-step explanation:

The length of the two pieces is 9/11 and 13/22

The original length of the rope = 2

Hence,

length of the remaining rope = 2 - 9/11 - 13/22

(Common denominator is LCM of 11 and 22, which is 22)

Length of remaining rope = 44/22 - 18/22 - 13/22

                                          = 13/22

Answer 2

GIVEN:-

Two pieces of lengths 9/11m and 13/22m are cut from a 2m long rope.

TO FIND:-

What is the length of the remaining rope.

SOLUTION:-

First let us find the sum of the cutout parts,

$\large\Rightarrow{\sf{\dfrac{9}{11}+\dfrac{13}{22}}}$

LCM of 11 and 22 is 22.

$\large\Rightarrow{\sf{\dfrac{18+13}{22}}}$

$\large\boxed{\sf{\dfrac{31}{22}\:m.}}$

Therefore,

Sum of two pieces of rope is 31/22.

Now the length of the remaining rope is,

$\large\Rightarrow{\sf{2-\dfrac{31}{22}}}$

LCM of 1 and 22 is 22.

$\large\Rightarrow{\sf{\dfrac{44-31}{22}}}$

$\large\boxed{\sf{\dfrac{13}{22}\:m.}}$

$\large{\green{\underline{\boxed{\therefore{\sf{\green{Length\:of\:remaining\:rope\:is\:\dfrac{13}{22}\:m.}}}}}}}$