Two pieces of metal, each weighing 3318 and 3054 gm respectively are to be made into cuboids of the same size. What is the maximum possible weight of each cuboid
Answers
Answered by
22
SOLUTION :
The maximum possible weight of each cuboid is equal to the HCF of 3318 and 3054 gm.
To find the HCF of these numbers here we use long division method for calculating HCF.
Given :
Weight of first metal piece = 3318 gm
Weight of second metal piece = 3054 gm
HCF of 3318 & 3054
3054)3318(1
3054
----------
264)3054(11
2904
-------
150 )264(1
150
---------
114)150(1
114
--------
36)114(3
108
------
6)36(6
36
------
0
HCF (3318 & 3054 ) = 6
Hence , the maximum possible weight of each cuboid is 6 gm.
HOPE THIS WILL HELP YOU….
The maximum possible weight of each cuboid is equal to the HCF of 3318 and 3054 gm.
To find the HCF of these numbers here we use long division method for calculating HCF.
Given :
Weight of first metal piece = 3318 gm
Weight of second metal piece = 3054 gm
HCF of 3318 & 3054
3054)3318(1
3054
----------
264)3054(11
2904
-------
150 )264(1
150
---------
114)150(1
114
--------
36)114(3
108
------
6)36(6
36
------
0
HCF (3318 & 3054 ) = 6
Hence , the maximum possible weight of each cuboid is 6 gm.
HOPE THIS WILL HELP YOU….
Answered by
11
Solution:-
given by:- two pieces of metal ,each weighting 3318 and 3054 gm.
we find us the maximum possible weight of each. we have,
take HCF of both weight 3318 and 3054.
by factorization,
3318 = 2×3×7×79
3054 = 2×3×509
HCF ( 3318, 3054 ) = 2×3 = 6
THE MAXIMUM POSSIBLE WAIGHT OF EACH = 6 GM.
■I HOPE ITS HELP■
given by:- two pieces of metal ,each weighting 3318 and 3054 gm.
we find us the maximum possible weight of each. we have,
take HCF of both weight 3318 and 3054.
by factorization,
3318 = 2×3×7×79
3054 = 2×3×509
HCF ( 3318, 3054 ) = 2×3 = 6
THE MAXIMUM POSSIBLE WAIGHT OF EACH = 6 GM.
■I HOPE ITS HELP■
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