Question

two pieces of wires enclose squares of area 5.76 and 12.25 respectively .the wires are joined together and made into a large square.calculate the area of the larger square. ​

Answer 1

Answer:

Area of the large square is 34.81 m²

Step by step explanation:

Given-

Area of First square is 5.76 m²

Area of Second square is 12.25 m²

To find - area of the larger square formed by both the wires.

Solution -

Area of first square= (side)²

5.76 = (side)²

√5.76 = side

side = 2.4 m

Area of second square =  (side)²

12.25 = (side)²

√12.25 = side

side = 3.5 m

Length of wire = perimeter of square

perimeter of first square = 4 (side)

                                         = 4(2.4)

                                         = 9.6 m

perimeter of second square = 4 (side)

                                               = 4(3.5)

                                               = 14 m

Total length of both the wires = 9.6 + 14 = 23.6 m

Length of both the wires = perimeter of larger square

perimeter of larger square = 4 (side)

                                  23.6   = 4(side)

                                  23.6/4 = side

                                   side  = 5.9 m

Area of larger square = (side)²

                                    = (5.9)²

                                    = 34.81 m²

Hope this will help you!!!

Please mark me the Brainliest!!!!