Question

two pillars fo equal height are on either side of a road , which is 100 m wide . The angles of elevation of the top of the pillars is 60 degree and 30 degree at a point on the road between the pillars. ( root 3 = 1.732 )

Answer 1

Answer:

hey

I got the answer

the correct ans is 43.3 m

Answer 2

Answer:

43.301 m

Step-by-step explanation:

Refer the attached figure

Let the height of the pillars i.e. AB and DE be h

In ΔABC

$Tan\theta = \frac{Perpendicular}{base}$

$Tan  60^{\circ}= \frac{AB}{BC}$

$\sqrt{3}= \frac{h}{x}$

$\sqrt{3}x= h$ ---1

In ΔCDE

$Tan\theta = \frac{Perpendicular}{base}$

$Tan  30^{\circ}= \frac{DE}{CD}$

$\frac{1}{\sqrt{3}}= \frac{h}{100-x}$

$\frac{1}{\sqrt{3}}(100-x)= h$ --2

Equate 1 and 2

$\sqrt{3}x= \frac{1}{\sqrt{3}}(100-x)$

$x=25$

So, Height of pillars = AB = $\sqrt{3}(25)= 43.301$

Hence the height of pillar is 43.301 m