Question

Two pillars of 15 meters and 20 meters standing right on the ground. If the distance between them is 12 meters, then find the distance between their upper extremities. (a) 11 m (b) 12m (c) 13 m (d) 14 m​

Answer 1

Answer:

v = final velocity

u = initial velocity

s = Distance

a = Acceleration

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✨ First case,

v = 0 m/s

u = 10 m/s

s = 20 m.

➡️ v^2 = u^2 + 2as

Or, 0 = 100 + 40a

Or, a = - 100 /40 = - 5/2.

.°. a = - 5/2 m/s^2

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✨Second case,

v = 0 m/s

u = 20 m/s

a = - 5/2 m/s^2

➡️ v^2 = u^2 + 2as

Or, 0 = 400 - 5s

Or, s = 400/5 = 80.

.°. The stopping distance will be 80 m.

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