Question

two pillars of equal height are on either side of road the width of the road is 100 M and angle of elevation of top of the pillar are 60 degree and 30 degree at a point on the road between the penis find the position of the point between the pillars and height of each pillar

Answer 1

I don't know the answer

Answer 2

Answer:

Step-by-step explanation:

Let AB and CD be the given pillars and let o the point of the observation on the road AC. Then

AngleAOB=60°

Angle COD= 30°

Angle OAB= 90°

Angle OCD=90°

And AC=150 m

Let AB=CD=h

Let OA=x m

Then, OC=(150-x)m

From right∆OAB,we have:

AB/OA= tan60°=√3=>h/x=√3=>h=√3x.....(i)

From right∆OCD,we have:

CD/OC=tan 30=1/√3

=>h/(150-x)=1/√3

=>h=(150-x)/√3....(ii)

From (i) and (ii)

√3x=(150-x)/√3

3x=150-x

x=75/2=37.5

From (i)

h=√3x

h=(37.5)√3

OR

h=37.5*1.732= 64.95(approx)