Two pillars of equal heights stand on either side of a road which is 150cm wide. At a point on the road between the pillars the angles of elevation at the tops of the pillars are 60° and 30° . Find the height of each pillar and the position of the point on the road from the first pillar. (Use √3=1.732)
Answers
Answered by
2

Let AB and CD be the poles and O is the point from where the elevation angles are measured.
In ΔABO,

In ΔCDO,

Since the poles are of equal heights,
CD = AB

DO = BD − BO = (150 − 37.5) m = 112.5 m
Therefore, the height of poles is

and the point is 37.5 m and 112.5 m far from these poles
Let AB and CD be the poles and O is the point from where the elevation angles are measured.
In ΔABO,

In ΔCDO,

Since the poles are of equal heights,
CD = AB

DO = BD − BO = (150 − 37.5) m = 112.5 m
Therefore, the height of poles is

and the point is 37.5 m and 112.5 m far from these poles
Similar questions