Question

Two pillers 50 and 61 high m feet are 60 m a ground. If a there the distance between their tops. c) Express as a Jurs 2 stand upright in apart, then find distance between their tops​

Answer 1

Answer:

Given: Two poles of heights 6m and 11m stand vertically upright on a plane ground. Distance between their foot is 12 m.

To find: Distance between their tops.

Let CD be the pole with height 6m.

AB is the pole with height 11m, distance between their foot i.e. DB is 12 m.

Let us assume a point E on the pole AB which is 6m from the base of AB.

Hence

AE = AB − 6 = 11 − 6 = 5 m

Now in right triangle AEC, Applying Pythagoras theorem

AC2 = AE2 + EC2

AC2 = 52 + 122 (since CDEB forms a rectangle and opposite sides of rectangle are equal)

AC2 = 25 + 144

AC2 = 169

AC=13cm

Thus, the distance between their tops is 13m.

Answer 2

Answer:

refer to the attachment

Step-by-step explanation:

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