Two pipes A and B are connected in parallel between two points. Pipe A is 150m long
and has a diameter off 15cm. pipe B is 100m long and has a diameter of 12cm. both pipes
have the same friction factor 0.018. A partially closed valve in pipe A causes discharge in
two pipes to be the same as shown in fig. Estimate the value of the valve coefficient. All
other minor losses can be neglected
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Answer:
Kl =18.62.
where, kl-valve coefficient.
Explanation:
since,both pipes having same discharges.
A1V1=A2V2.
Pi/4 (0.15)² V1= Pi/4 (0.12)² V2.
V2=(0.15/0.12)² V1.
V2=1.5625 V1.-----------(1)
loss in the valve will be kl (V1²/2g).
head losses are same in the Both pipes.
hence,
(f1 l1 V1 ²/2g d1)+kl (V1²/2g)= (f2 l2 V2 ²/2g d2).
get the equation (1) and substitute in the above formulae.
we get,
18+kl=36.62.
kl=18.62.(this is the valve coefficient for the given condition.)
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