Math, asked by premnarayan83, 1 year ago

two pipes A and B can fill a cirtern in 3 hrs and 4 hrs respectively and a third pipe can empty it in two hrs. if all the three pipes are opened when the the tank is empty , hwo many hours will it take to fill the tank?

Answers

Answered by avhibunty
0
Pipe A: 1/3 in one hour
Pipe B: 1/4 in one hour
Pipe C: -1/2 in one hour
Net part filled in 1 hour = (1/3+1/4-1/2)
= (4+3-6/12)
= 1/12

The tank will be fill in 12 hour.
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