Math, asked by aradhyabharti2011, 2 months ago

Two pipes A and B can fill a cistern in 20 minutes and 30 minutes
respectively. If these pipes are turned on alternately for 1 minute each
how long will it take to the cistern to fill?

Answers

Answered by mahakkori749
0

Answer:



24

Q:

Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respectively . If these pipes are turned on alternately for 1 minute each how long will it take to the cistern to fill? 

Answer:

As the pipes are operating alternatively, thus their 2 minutes job is = 14 + 16 = 51214 + 16 = 512 

In the next 2 minutes the pipes can fill another 512512 part of cistern. 

Therefore, In 4 minutes the two pipes which are operating alternatively will fill 512 + 512 = 56512 + 512 = 56Remaining part = 1 − 56 = 161 - 56 = 16 

Pipe A can fill 1414 of the cistern in 1 minute 

Pipe A can fill 1616 of the cistern in = 2323 min 

Therefore, Total time taken to fill the Cistern  

4 + 2323 minutes.

Step-by-step explanation:

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aradhyabharti2011: thank you
Answered by KrisGalaxy
12

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