Two pipes A and B can fill a cistern in 2hour and 150 minutes. There is an outletcal C. If all the three pipes are openedtogether, the tank is full in 100 minutes. How much time will be taken by C to empty the full tank?
Answers
Answered by
0
Answer:
12 hours
Step-by-step explanation:
Part of the tank filled when all the three pipes are opened for 10 hours
=10×(
15
1
+
20
1
−
25
1
)=10×(
300
20+15−12
)=
300
230
=
30
23
Remaining empty part = 1−
30
23
=
30
7
Part of the tank filled in 1 hour by pipes (A and B) =
15
1
+
20
1
=
60
4+3
=
60
7
∵
60
7
part is filled in 1 hour
30
7
part is filled in 2 hours
∴ Total time to fill the tank =10+2=12 hours
Similar questions