Two pipes a and b can fill a tank in 12 hours and 15 hours respectively. If they are opened on alternate hours with pipe a opened first, then in how many hours the tank will be full?
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Answer:
13.3 hours
Step-by-step explanation:
2 hours work of a and b is=1/12 + 1/15
=3/20 is 2 hrs work of a and b
if 2 hours work is 3/20 of total work then 1 (total work) will be
2/(3/20)=40/3=13.33
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