Math, asked by ManjuGupta3471, 1 year ago

Two pipes a and b can fill a tank in 12 hours and 15 hours respectively. If they are opened on alternate hours with pipe a opened first, then in how many hours the tank will be full?

Answers

Answered by sunnysinghdollysingh
2

Answer:

13.3 hours

Step-by-step explanation:

2 hours work of a and b is=1/12 + 1/15

=3/20 is 2 hrs work  of a and b

if 2 hours work is 3/20 of total work then 1 (total work) will be

2/(3/20)=40/3=13.33

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