Two pipes A and B can fill a tank in 15 and 12 hours respectively. Pipe B alone is kept open for 3/4 of the
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as b alone is open for 3/4 time.
the remaining time is 1-3/4=1/4
let x be the time required to fill tank
3x/4(1/12)+1x/4(1/12+1/15)=1
x/16+x/48+x/60=1
lcm of 16,48,60=240
(15x+5x+4x)/240=1
24x=240
x=10hrs.
so tank is filled in 10hrs
the remaining time is 1-3/4=1/4
let x be the time required to fill tank
3x/4(1/12)+1x/4(1/12+1/15)=1
x/16+x/48+x/60=1
lcm of 16,48,60=240
(15x+5x+4x)/240=1
24x=240
x=10hrs.
so tank is filled in 10hrs
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