two pipes A and B can fill a tank in 15 hours and 20 hours respectively while a third pipe C can empty the full tank in 25 hours. All the three pipes are opened in the beginning. After 10 hours, in how much time, will the tank be full?
Answers
QUESTION :
two pipes A and B can fill a tank in 15 hours and 20 hours respectively while a third pipe C can empty the full tank in 25 hours. All the three pipes are opened in the beginning. After 10 hours, in how much time, will the tank be full?
ANSWER :
If all the three pipes are kept open ,in 1 hour ,
60/7 — 1/25 = 23/300 part of the tank get filled.
So ,in 10 hours 23/300 ×10 =23/30 part of the tank get filled .
Now pipe c is closed after 10 hours .
If all the three pipes are kept open ,in 1 hour ,
60/7 — 1/25 = 23/300 part of the tank get filled.
So ,in 10 hours 23/300 ×10 =23/30 part of the tank get filled .
Now pipe c is closed after 10 hours .So the remaining 1–23/30 = 7/30 part of the tank can be filled by A&B pipe in
If all the three pipes are kept open ,in 1 hour ,60/7 — 1/25 = 23/300 part of the tank get filled. So ,in 10 hours
23/300 ×10 =23/30 part of the tank get filled .
Now pipe c is closed after 10 hours .So the remaining 1–23/30 = 7/30 part of the tank can be filled by A&B pipe in
7/30 ÷7/60 = 7/30 ×60/7
I
f all the three pipes are kept open ,in 1 hour ,
60/7 — 1/25 = 23/300 part of the tank get filled. So ,in 10 hours 23/300 ×10 =23/30 part of the tank get filled .
Now pipe c is closed after 10 hours .
So the remaining 1–23/30 = 7/30 part of the tank can be filled by A&B pipe in 7/30 ÷7/60 = 7/30 ×60/7 = 2 hours
FINAL ANSWER : 2hrs.
Answer:
2 hours
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