Math, asked by ramya172ft128, 9 months ago

Two Pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 6 minutes, pipe B is turned off. What is the total time required to fill the tank?

Answers

Answered by mastermimd2

Step-by-step explanation:

Part filled in 4 minutes =4(1/15+1/20) = 7/15

Part filled in 4 minutes =4(1/15+1/20) = 7/15 Remaining part =(1-7/15) = 8/15

Part filled in 4 minutes =4(1/15+1/20) = 7/15 Remaining part =(1-7/15) = 8/15 Part filled by B in 1 minute =1/20 : 8/15 :: 1:x

Part filled in 4 minutes =4(1/15+1/20) = 7/15 Remaining part =(1-7/15) = 8/15 Part filled by B in 1 minute =1/20 : 8/15 :: 1:x x = (8/15*1*20) = 1023min = 10min 40sec

Part filled in 4 minutes =4(1/15+1/20) = 7/15 Remaining part =(1-7/15) = 8/15 Part filled by B in 1 minute =1/20 : 8/15 :: 1:x x = (8/15*1*20) = 1023min = 10min 40secThe tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec

Answered by ramya320858

Answer:

10hrs 30mins

Step-by-step explanation:

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