Two pipes A and B can fill a tank in 16 hours and 20 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
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Pipe A alone can fill the tank = 16 hrs
Pipe B alone can fill the tank = 20 hrs
Time ratio of Pipe A and B = 16 ∶ 20 = 4 ∶ 5
As we know,
Efficiency is inversely proportional to time.
Efficiency ratio of pipe A and B = 5 ∶ 4
Total work = 5 × 16 = 80
Both pipes opened alternately for 1 hr
Total work in 2 hrs = 5 + 4 = 9
Work in 16 hrs = 9 × 8 = 72
Work in next 1 hr (17th) = 72 + 5 = 77
Remaining work = 80 - 77 = 3
B alone can 4 work in = 1 hr
B alone can 3 work in = 3/4 hr
So, total work completed in hrs
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