Two pipes A and B can fill a tank in 20 and 16 hours respectively. Pipe B alone is kept open for 1/4 of time and both pipes are kept open for remaining time. In how many hours, the tank will be full?
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Explanation: => Let the required time be x hours, then
1/16(1/4x ) + 1/16(x-1/4x) + 1/20 (x-1/4x) = 1
⇒ x/16+3x/80 = 1
⇒ x= 10 hours.
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