Two pipes A and B can fill a tank in 30 and 15 mins.
Both are opened but at the time when tank was about
to full a third pipe C was opened to pump the water
out. After 5 minutes the tank was full. In how much
time C can empty the tank?
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Answer:
Step-by-step explanation:
Part of the istern filled when the two pipes are opened simultaneously =
30
1
+
15
1
=
30
1+2
=
10
3
=
10
1
,
i.e. The two pipes can fill the cistern together in 10 hours.
Together with the leak, the cistern can be filled in (10+5) hours =15 hours.
Let the leak take x hours to empty the cistern. Then,
10
1
−
x
1
=
15
1
⇒
x
1
=
10
1
−
15
1
=
30
1
∴ The leak takes 30 hours to empty the cistern
pls edit accordingaly
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