Question

Two pipes A and B can separately fill a tank in 12 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank

Answer 1

Answer:

Step-by-step explanation:

Let capacity be x litre

Rate of A and B = x/ 12 + x/ 15 = 9x / 60

work done by A and B in 15 minutes = 9x / 60 * 15 = 9x/ 4 litre

Negative work done by c in 15 minutes = 45*15 = 675 litre

9x / 4 - 675 = x

x = 540 litre capacity

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Answer 2

Answer:

The capacity of the tank is 540 liters

Step-by-step explanation:

Let x be the time taken by the pipe C to drain off the 45 liters if water per mintue

Then

For a pipe A = 1/12

For a pipe B = 1/15 for one minute

so

1/12+1/15-1/x= 1/15

(15x)+(12x)-(15×12) = 1/15

180x

27x -180 = 1/15

180x

27x -180 = 12x

27x-12x = 180

15x = 180

x= 180/15

x= 12

The capacity of the tank is total water drain off from the pipe C

45liters × 12 = 540 liters