Math, asked by sharmanaman4090, 1 year ago

Two pipes a and b can separately fill a tank in 2 hours and 3 hours respectively. if both the pipes are opened simultaneously in the empty tank, then the tank will be filled in

Answers

Answered by Anonymous
30
Pipe A fills the tank in 2 hrs
Pipe A in 1 hr fills : 1/2 part of tank
Pipe B fills the tank in 3 hrs
Pipe B in 1 hr fills: 1/3 part of tank
In 1 hr, both fill:
1/2 + 1/3 = 3+2/6 = 5/6 part
1 hr=== 5/6 part
X hrs == 1 part
5X/6 = 1
X = 6/5 hours OR 6*60/5 = 72 mins or 1 hr 12 mins
So both the pipes working together will fill the tank in 72 mins or 1 hr 12 mins
Hope it helps
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