Two pipes A and B can separately fill a tank in 36 minutes and 45 minutes respectively. If both the pipes are opened simultaneously, how much time will it take to fill the tank.
Answers
Answered by
61
Step-by-step explanation:
In 1 min pipe A can fill 1/36 of tank
In 1 min pipe B can fill 1/45 of tank
If both of them are left open simultaneously then total tank filled in 1 min=1/36+1/45=1/20
Therefore total time required to fill the tank=1/(1/20)=20minutes
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Answered by
10
Answer:
Step-by-step explanation:
In 1 minute pipe A can fill 1/36 of tank
In 1 minute pipe B can fill 1/45 of tank
If both of them are left open
Simultaneously, then total tank filled in 1 minute =1/36+1/45 = 1/20
Therefore, total time required to fill the tank= 1/(1/20)=20 minutes.
Hope it's help you.......
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