Math, asked by YogeshChaudhary9922, 11 months ago

Two pipes A and B can separately fill a tank in 36 minutes and 45 minutes respectively. If both the pipes are opened simultaneously, how much time will it take to fill the tank.

Answers

Answered by Chirag026
61

Step-by-step explanation:

In 1 min pipe A can fill 1/36 of tank

In 1 min pipe B can fill 1/45 of tank

If both of them are left open simultaneously then total tank filled in 1 min=1/36+1/45=1/20

Therefore total time required to fill the tank=1/(1/20)=20minutes

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Answered by gnjha1975
10

Answer:

Step-by-step explanation:

In 1 minute pipe A can fill 1/36 of tank

In 1 minute pipe B can fill 1/45 of tank

If both of them are left open

Simultaneously, then total tank filled in 1 minute =1/36+1/45 = 1/20

Therefore, total time required to fill the tank= 1/(1/20)=20 minutes.

Hope it's help you.......

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