two pipes A and B is can fill a tank in six hours and eight hours respectively .if they are opened in alternate hours starting inA. the number of hours needed to fill the tank is
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Answer:
6 3/4 hours
Step-by-step explanation:
Two pipes A and B can fill a tank in 6 hours and 8 hours respectively.
Take LCM of 6 and 8
Total work = 24
No of days or hours * one day or hour work (or) efficiency = Total work
One day work of A = 24/6 = 4
One day work of B = 24/8 = 3
Total efficiency = 7
In 2 days 7 work can be done ( since it is working on alternative hour)
On dividing 24/7,
Quotient = 3 and Remainder 3
A and B work alternative = 3*2 = 6 hours
In days 21 work is completed.
Remaining 3 work is completed by A = 3/4 hours
A and B can work alternatively and complete a work in 6 3/4 hours
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