Math, asked by Asmiya12, 8 months ago

Two pipes A and B running together can fill a tank in 3 1/3 minutes if pipe B takes .5 minutes more than pipe A to fill the tank separately, than find the time in which each pipe would fill the tank separately.

Answers

Answered by Anonymous
224

\huge{\orange{\underline{\red{\mathbf{HEY}}}}}

\huge{\orange{\underline{\red{\mathbf{BRAINLY\:USER}}}}}

\huge{\orange{\underline{\blue{\mathbf{Here\:is\:your}}}}}

\huge{\orange{\underline{\pink{\mathscr{Answer}}}}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

\\

⎟⎟✪✪ QUESTION ✪✪⎟⎟

\\

Two pipes A and B running together can fill a tank in 3 1/3 minutes if pipe B takes .5 minutes more than pipe A to fill the tank separately, than find the time in which each pipe would fill the tank separately.

\\

⎟⎟✪✪ ANSWER ✪✪⎟⎟

\\

Let the time taken by pipe A =x

and by pipe B =y

ATQ

x + y = 31/3

3x+3y=31−−−−(1)

x = y+5

3(x-y=5)

3x-3y =15 -----------------------------(2)

add equation (1)&(2)

3x+3y =31

+ 3x-3y =15

= 6x = 46

x =46/6

x = 7.33

time taken by A =7.33m

time taken by B = 7.33-5=2.33

Similar questions