Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
A.1 hour
B.2 hours
C.6 hours
D.8 hours
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(A+B) can fill the cistern in 4 hrs
(A+B)'s 1 hr work =1/4
let A can fill it in x hrs
B can fill it in (x+6)hrs
A's 1 hr work 1/x
B's 1 hr work 1/x+6
(A+B)'s 1 hr work =1/x+1/x+6
But given (A+B)'s 1 he work =1/4
So,
1/x+1/x+6=1/4
By solving it X1=-4 X2=6
Hence 6 hrs will be the answer (time is in always positive integer)
(A+B)'s 1 hr work =1/4
let A can fill it in x hrs
B can fill it in (x+6)hrs
A's 1 hr work 1/x
B's 1 hr work 1/x+6
(A+B)'s 1 hr work =1/x+1/x+6
But given (A+B)'s 1 he work =1/4
So,
1/x+1/x+6=1/4
By solving it X1=-4 X2=6
Hence 6 hrs will be the answer (time is in always positive integer)
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